Alice Law Version 7

 

The Experiment Of Alice Law

 

Han Erim

May 7, 2012

Copyright © 2012 Han Erim, All Rights Reserved.

 

 

THE EXPERIMENT OF THE ALICE LAW

The thing that surprised me most after I started to study on physics was to see that physics was abandoned. Some important experiments that can guide us about the general theory of physics were never brought to the agenda and never carried out. Therefore, the general theory of physics unfortunately got stuck with assumptions and methods. Can the general theory of physics be established with assumptions? You certainly make a mistake at some point. The mistake made in the Electromagnetic Theory is a good example for this. 

In this section, I will express my own thoughts on how (c+v)(c-v) Mathematics can be verified empirically for the Electromagnetic Theory. This experiment can suggest that the electromagnetic interaction occurs through fields and light travels inside fields. The logical principle of the experiment has been established upon the determination of whether light carries the momentum of the source that emits it. 

I hope that the experiment that I offered can be done in the best circumstances and as soon as possible. Of course, other experiments can be planned and carried out for the verification of (c+v)(c-v) mathematics. 

 

As can be seen in the figure, there are two frames, A and B, which move in the direction of their own X axes. There is a lamp as the light source in the B frame. We suppose that the lamp create the light as a small packet that does not spread around.

Our question is this: In order for the light to reach the A frame, at which point should the B frame send the light?

I publicly say this loud and clear: No physicist knows the answer to this question at present. Not being able to answer such a question indicates that there is a huge lack of information physics because this information does not require having a specialization. This question and all other similar questions included in the scope of similar general physics information should certainly be answered in physics. 

Laugh away anyone saying that they know the answer because they certainly talk through their hats. If they knew the answer, they would also know what I wrote here. Whoever they are, the answers they give do not carry a meaning other than expression their own predictions. That is the most dangerous thing in physics to assume that you know because; when the assumptions are regarded as truths, trouble will eventually begin at a weak spot sooner or later. 

The answer to this question is about whether the light carries the momentum of the source that emits it. Accordingly, this question can be answered with two different assumptions. We will analyze both these answers here. As a result of these analyses, we will try to figure out whether we can plan an experiment that can reveal the difference between the two opinions.

Alternative 1: The light carries the momentum of the source that emits it. 

Letís release a stone to fall from a mast and repeat the same thing a few times. The stone will always fall into the same place whether the ship stays still or moves because the stone moves with the ship and has the momentum in the direction of the shipís movement. We can apply this example to ours.

In order to make it easy, letís think that the A frame is stable. If the light carries the momentum of the source that emits it, the light will travel by following the blue Y axis that belongs to the B frame. In other words, as in the stone example above, the light will keep the speed of the B frame, which emits the light, on X axis. Accordingly, the B frame must send the light before it comes to the same X position with the A frame. As a conclusion, if this alternative is true, the light will travel by following the blue Y axis that belongs to the B frame. As can be seen in the figure, at the arrival time of the light, the Y axes overlap. 
Alternative 2: The light does not carry the momentum of the source that emits it. 

In order to make it easy, letís again think that the A frame is stable. If the light does not carry the momentum of the source that emits it, the B frame must send the light the moment it comes to the same X position with the A frame. In this case, the Y axes overlap at the emitting time of the light as can be seen in the figure. 

In this alternative, since the light does not carry the momentum of the B frame, it will travel independent of the B frame. Accordingly, the light will travel the red Y axis that belongs to the A frame.
Figure 1-A = Figure 2-A

Alternative 1: The light carries the momentum of the source that emits it.

Letís change our point of view here. Let's assume that the B frame is stable and the A frame is in motion. As changing our point of view does not change the incident that comes about, we should obtain the same results as we did before in the previous situations that we examined before. Letís remember; we saw in almost every section that it does not matter whether the A frame or the B frame is in motion. The important thing was that both the frames are in motion according to each other and we needed to obtain the same results independent of the frame that we took as base.

We transfer the result in the 1-A figure without changing it. If the light carries the momentum of the source that emits it, the light will travel by following the blue Y axis that belongs to the B frame. The B frame must send the light the moment it comes to the same X position with the A frame. The light will follow the blue Y axis. At the emitting time of the light, the Y axes overlap. 

Please pay attention to the incident coming about in the figure 2-A. For this alternative, the movement of the A frame does not have an effect on the light that comes towards itself. We will use this result onwards. 
Figure 1-B = Figure 2-B

Alternative 2: The light does not carry the momentum of the source that emits it.


Lastly, by supposing that the B frame is stable and that the A frame is in motion, letís write the situation that come about for this alternative. We need to get the same result for this alternative as we did in the figure 1-B. We transfer what we wrote there without changing it. 

The B frame must send the light before it comes to the same X position with the A frame. At the emitting time of the light, the Y axes overlap. The light will travel by following the red Y axis. 

Please take a look here; how interesting a situation occurred in the figure 2-B. The light changed its direction as the A frame was in motion. In this alternative, we see that a situation comes about, which we can describe as ďThe light carries the momentum of its arrival target.Ē. We can say this because, in order for the light to reach the frame A, the speed of light on X axis should be equal to the speed of the A frame on X axis. So letís write this alternative in its new form:

Alternative 2: The light carries the momentum of its arrival target.

We found out a clear difference for both the alternatives. Now we can plan an experiment by benefiting from the results that we obtained in the figures 2-A and 2-B 
Alternative 1: The light carries the momentum of the source that emits it.
Alternative 2: The light carries the momentum of its arrival target.

We examined both the views here. Now, letís try to decide which one may be correct. Of course, no matter what we think of and what we decide on here, this detail must certainly be determined with an experiment. But we will make our discussion it here anyway.

Although Alternative 1, namely the fact that the light carries the momentum of the source that emits it, may seem sensible, it contradicts with a very important hypothesis in physics. Look what Albert Einsteinís Universal Velocity of Light Postulate says:

Universal Velocity of Light: The light is always propagated in empty space with a definite velocity c which is independent of the state of motion of the emitting body

If you say that the first alternative is correct, then I will tell you ďPlease rearrange the postulate and then confront me. Look, there it says that the light is independent of the source it is emitted from.Ē Of course, it is almost impossible to change this postulate because even a minor change on it will lead to the loss of the Relativity Theory. Besides, it is not such an unknown subject that the light is independent of the source it is emitted from. 

The second alternative, on the other hand, does not contradict with the Universal Velocity of Light postulate. However, it currently contradicts with the Electromagnetic Theory because it is not described in the Electromagnetic Theory in any way that the light carries the momentum of its arrival target (remember the figure 2-B). The acceptance of this alternative leads to the Electromagnetic Theory (or, letís say, we become obliged to change the mistake that it carries). The fact that the light behaves in this way is described in the ALICE LAW and its (c+v)(c-v) mathematics, but it is not verified empirically either. 

What then? What will we do if no consistent result comes about? No matter which alternative we choose, some other things in physics are pushed beyond their limits or get harm. If you have a different opinion on how to answer this question, please come forward and tell about that or we may conduct an experiment and see the results together. Let the experiment determine the solution. If such an experiment is not carried out, we will never know the answer to this question.
ANALYZE I have prepared an animation so that we can analyze the topic with all its aspects. You can move any of the frames A and B that you like in the animation. You can see what kinds of results come about for both the alternatives. 

 

THE EXPERIMENT THAT THE ALICE LAW SUGGESTS FOR THE RELATIVITY THEORY AND THE ELECTROMAGNETIC THEORY

(c+v)(c-v) is a mathematics that the electromagnetic theory should take as base. It is also the mathematics of the Relativity Theory. I have mentioned these before.

An experiment to verify (c+v)(c-v) mathematics can only be carried out by measuring the speed of light that is sent from a stable frame to a moving one. In such an experiment, the speed of the light should be measured from the stable frame that sends the light. In the measurements made from the frame that is arrival target of the light, (c+v)(c-v) mathematics does not come about and the speed of light is measured to be ďcĒ. I have explained the reason of this in many parts of this study. I do not want to repeat it here. 

In fact, it is easy to design experiments on (c+v)(c-v) mathematics. However, when it comes to practice, it is extremely hard to conduct these experiments because light is very fast. Moreover, If the light were not so fast, we would not be talking about these now. 

In the previous part, we examined whether the light carries the momentum of the source that emits it and we obtained two alternatives. These alternatives were as follows:

Alternative 1: The light carries the momentum of the source that emits it.
Alternative 2: The light carries the momentum of its arrival target.

If we can empirically identify which alternative is the correct one, we will obtain a crucial result on (c+v)(c-v) mathematics. For this purpose, I have designed an experiment that I think practicable. I will tell you about this experiment here.

THE WAY TO CONDUCT THE EXPERIMENT 

This experiment uses the situations that come about in the figures 2-A and 2-B as base. There is a square platform and there is the second, rotatable platform in the middle of the square. The light coming from the light source is channeled in a line onto the entire platform. Here, the stable frame is the light source (FRAME B) and the mobile frame is the rotating platform (FRAME A). We rotate the platform at the fastest possible speed and take the photograph of the light line that we dropped onto the platform. 

I think the rotation speed of the platform that will be used in this experiment must exceed all the world records multiple times. Maybe the light source should be far as miles. Namely, this is not an easy experiment and, to tell the truth, I do not know if it can be done in practice either. This is an engineering question and I cannot answer these. I only make suggestions here. If you ask me what kind of a result will be obtained from this experiment, then I can give an answer to that with my own opinion.


1) If the light carries the momentum of the source that emits it, there will not be a change on the light line channeled on the platform (the situation we obtained in the figure 2-A). Accordingly, the light line will seem as a straight line in the photograph. 

2) If the light carries the momentum of its arrival target, while the light comes towards the rotating platform, it will change its direction by being influenced by the rotation movement of the platform (the situation we obtained in the figure 2-B). The light line will draw away from its ideal situation depending on the distance of the light source and the rotation speed of the platform. The light line on the rotating platform will appear inclined in the photograph. 

WHY DOES LIGHT CARRY THE MOMENTUM OF ITS ARRIVAL TARGET?

The answer to this question is certain for the Alice Law.

Firstly, the light beam is a group of electromagnetic waves and it includes infinite number of electromagnetic waves. 

The electromagnetic waves, on the other hand, travels in fields rather than in space. The electromagnetic interaction occurs through FIELDs. Each object has its own field. When the object moves, it also moves the field that belongs to it along with itself. If the object is in motion, the electromagnetic waves on the field are carried together with the field. The rotation of the platform carries the electromagnetic waves that travel inside the field of rotating platform in the rotation direction.

The rotating platform is a group of objects. It is possible to regard even the smallest part that constitutes the platform as a separate object. To be able to make reasoning, it is enough to think that every spot on the field of the rotating platform has its own field. The movement of an electromagnetic wave going towards the spot target on the rotating platform can only be dependent on the movement of that spot because it moves inside that spot's field. The thing carrying the momentum is not the electromagnetic wave in reality but the field belonging to that spot.

Crazy, is not it? I also think so.

THE RESULTS OF THE EXPERIMENT

The results of this experiment are really profound. No matter in what way this experiment is concluded, it will be very influential on the general theory of physics. It is a fact that some mistakes were made in the basic theory of the physics. This experiment will show us where these mistakes were made and what is correct. 

Of course, my heart wishes that this experiment would lead to such a certain result that it would prevent any kind of argument and that it would verify (c+v)(c-v) mathematics because this is for the benefit of everyone. In that case, the Electromagnetic Theory and the Relativity Theory would combine and both these theories would get rid of their lacks mistakes substantially. The future of physics would be open and physics would go a lot further.

If an opposite result comes about, I think that would be really bad because we would get into a dark era in which we would not know what is true and what is not in physics. This is not an desirable thing.

I am not pessimist about the result of this experiment at all because I will be committing myself to Albert Einsteinís Universal Velocity of Light postulate. I have always believed in that postulate.

 

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